A force acts on a 30 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t3³ where x is in metres nd t is in seconds. The work done during the first 4 second is ___________

  • 5.28 J 
  • 450 mJ 
  • 490 mJ 
  • 530 mJ
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